At 300 K, the vapour pressure of a solution containing 1 mole of n-hexane and 3 moles of n-heptane is 550 mm of Hg. At the same temperature, if one more mole of n-heptane is added to this solution, the vapour pressure of the solution increases by 10 mm of Hg. What is the vapour pressure in mmHg of n-heptane in its pure state ?
At 300 K, the vapour pressure of a solution containing 1 mole of n-hexane and 3 moles of n-heptane is 550 mm of Hg. At the same temperature, if one more mole of n-heptane is added to this solution, the vapour pressure of the solution increases by 10 mm of Hg. What is the vapour pressure in mmHg of n-heptane in its pure state ?
Asked by Shiksha User
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1 Answer
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P? = X? (P? – P? ) + P?
ATQ
550 = 1/4 (P? – P? ) + P?
2200 = P? – P? + 4P?
560 = 1/5 (P? – P? ) + P?
2200 = P? – P? + 5P?
P? + 3P? = 2200
P? + 4P? = 2800
P? = 600
P? = 400 mmHg
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