At $25 ° C$ and 1 atm pressure, the enthalpy of combustion of benzene (I) and acetylene (g) are -3268 kJ mol^-1 and -1300 kJ mol^-1, respectively. The change in enthalpy for the reaction 3C₂H₃(g) ® C₆H₆(I), is

Option 1 - +324 kJ mol-1

Option 2 - +632 kJ mol-1

Option 3 - -632 kJ mol-1

Option 4 - -732 kJ mol-1

2 Views|Posted 7 months ago

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Vishal Baghel | Contributor-Level 10

7 months ago

Correct Option - 3

Detailed Solution:

$Δ H = 3 {(Δ H_{c o m b})}_{C_{2} H_{2} (g)} - {(Δ H_{c o m b})}_{C_{6} H_{6} (l)}$

$= - 1300 * 3 - (- 3268) k J / m o l e$

$= (- 3900 + 3268) k J / m o l e$

$= - 632 k J / m o l e$

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