Borazine, also known as inorganic benzene, can be prepared by the reaction of 3-equivalents of “X” with 6-equivalents of “Y”. 'X' and “Y”, respectively are:

Option 1 - <p>B(OH)<sub>3</sub> and NH<sub>3</sub></p>
Option 2 - <p>B<sub>2</sub>H<sub>6</sub> and NH<sub>3</sub></p>
Option 3 - <p>B<sub>2</sub>H<sub>6</sub> and HN<sub>3</sub> and B<sub>2</sub>O<sub>3</sub></p>
2 Views|Posted 8 months ago
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8 months ago
Correct Option - 2
Detailed Solution:

B 2 H 6 + N H 3 H i g h T e m p e r a t u r e B 3 N 3 H 6 ( B o r a z i n e )

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ΔG° = –RT * 2.303 log K

–nFE° = +RT * 2.303 log K

2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K

10 = log10 K = 1010

It has chiral centre and differently di substituted double bonded carbon atoms.

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Chemistry The p-Block Elements

Chemistry The p-Block Elements

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