C2H5OH + KMnO4 --> HC2H3O2 +MnO2 + KOH + H2O is the unbalanced equation if 5g of ethanol & excess amount of aqueous KMnO4 are reacted and 5.5g of HC2H3O2 result. What is the percent yield in the nearest integer? [Given: Atomic mass of H = 1, C = 12, O = 16]
C2H5OH + KMnO4 --> HC2H3O2 +MnO2 + KOH + H2O is the unbalanced equation if 5g of ethanol & excess amount of aqueous KMnO4 are reacted and 5.5g of HC2H3O2 result. What is the percent yield in the nearest integer? [Given: Atomic mass of H = 1, C = 12, O = 16]
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C? H? + 5O? → 3CO? + 4H? O
C? H? + (13/2)O? → 4CO? + 5H? O
∴ 2 mol C? H? is given
∴ 13 mol O? is required for combustion of Butane
∴ Total mol of O? = 5 + 13 = 18
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