Calculate the oxidation number of each sulphur atom in the following compounds:

(a) Na₂S₂O₃

(b) Na₂S₄O₆

_{(c) Na₂SO₃}

_{(d) Na2SO4}

<p><strong> (a) </strong>let x=&nbsp;oxidation number of &nbsp;&nbsp;sulphur, and &nbsp;&nbsp;+1 is oxidation number of Na, -2 is oxidation number of&nbsp;O, also we can assume total charge on compound = 0 then solving we get.</p><p>+2 + 2x - 6 = 0&nbsp;</p><p>x = +2.&nbsp;</p><p><strong> (b)&nbsp;</strong>let x=&nbsp;oxidation number of &nbsp;&nbsp;sulphur, and &nbsp;&nbsp;+1 is &nbsp;&nbsp;oxidation number of Na, -2 is oxidation number of O, also we can assume total charge on compound = 0 then solving we get.</p><p>+2 + x - 6 = 0</p><p>x = +4</p><p>&nbsp;</p><p><strong> (c) </strong>let x= oxidation number of &nbsp;&nbsp;sulphur, and &nbsp;&nbsp;+1 is &nbsp;&nbsp;oxidation number of Na, -2 is oxidation number of O, also we can assume total charge on compound = 0 then solving we get.</p><p>+2 + x - 6 = 0</p><p>x = +4</p><p><strong> (d)&nbsp;</strong> let x=&nbsp;oxidation number of sulphur, and &nbsp;+1 is &nbsp;&nbsp;oxidation number of Na, -2 is oxidation number of O, also we can assume total charge on compound = 0 then solving we get.</p><p>+2 + x - 8=0</p><p>x = +6.</p><p>&nbsp;</p>

0 Upvotes 0 Upvotes 0 Downvotes

• • Report Abuse
• Comment