Choose the correct option for graphical representation of Boyle's law, which shows a graph of pressure vs. volume of a gas at different temperatures :

Option 1 - <p>A graph showing P vs V with curves for 200K, 400K, 600K.<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 2 - <p>A graph showing P vs V with straight lines from origin for 200K, 400K, 600K.<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 3 - <p>A graph showing P vs V with straight lines from origin for 200K, 400K, 600K.<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 4 - <p>A graph showing P vs V with curves for 600K, 400K, 200K.</p>
2 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
V
5 months ago
Correct Option - 4
Detailed Solution:

According to Boyle's law

P ∝ 1/V

At a given pressure,

V ∝ T

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Chemistry NCERT Exemplar Solutions Class 11th Chapter Eleven 2025

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