Consider an imaginary ion  The nucleus contains ‘a’% more neutrons that the number f electrons in the ion. The value of ‘a’ is____________. [nearest integer]

 Number of neutrons = 26

Number of electrons = 25

% of extra electrons = $\frac{26-25}{25}\times 100=4\mathrm{\%}$

<div><div>&nbsp;<picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1752733263phpHkYJqe.jpeg" alt="" width="52" height="37" loading="lazy"></picture>Number of neutrons = 26</div></div><p>Number of electrons = 25</p><p>% of extra electrons =&nbsp;<math><mrow><mfrac><mrow><mn>2</mn><mn>6</mn><mo>−</mo><mn>2</mn><mn>5</mn></mrow><mrow><mn>2</mn><mn>5</mn></mrow></mfrac><mo>×</mo><mn>1</mn><mn>0</mn><mn>0</mn><mo>=</mo><mn>4</mn><mn>%</mn></mrow></math></p>

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