Consider the reaction

4HNO3(l) + 3 KCl(s) → Cl2(g) + NOCl(g) + 2H2O(g) + 3KNO3(s)

The amount of HNO3 required to produce 110.0g of KNO3 is

(Given: Atomic masses of H, O, N and K are 1, 16, 14 and 39, respectively)

Option 1 - <p>32.2g&nbsp;</p>
Option 2 - <p>69.4g&nbsp;&nbsp;&nbsp;</p>
Option 3 - <p>91.5g&nbsp;</p>
Option 4 - <p>162.5g</p>
7 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
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7 months ago
Correct Option - 3
Detailed Solution:

4HNOI3 (l)+3KCl (s)Cl2 (g)+NOCl (g)+2H2O (g)+3KNO3 (g)

4 moles of HNO3 produced 3 mol of KNO3

Here mole of produced KNO3110101

If 3 mol of KNO3 produced by 4 moles of HNO3

 1 mole of KNO3 produced by 43 moles of HNO3

and 110101 mole of KNO3 produced by 4*1103*101 moles of HNO3 = 1.45 mole of HNO3

Hence mass of HNO3 = mole * mol.wt = 145 * 63 = 91.48  91.5gm

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Chemistry Ncert Solutions Class 11th 2023

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