Chemistry Coordination Compounds Class 12th Chemistry

Correct electronic configuration of cobalt in complex cation ${[C o {(N H_{3})}_{6}]}^{3 +}$ is (Atomic No. of Co is 27)

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <msubsup> <mrow> <mi>t</mi> </mrow> <mrow> <mn>2</mn> <mi>g</mi> </mrow> <mrow> <mn>4</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>e</mi> </mrow> <mrow> <mi>g</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msubsup> </mrow> </math> </span></p>

Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <msubsup> <mrow> <mi>t</mi> </mrow> <mrow> <mn>2</mn> <mi>g</mi> </mrow> <mrow> <mn>4</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>e</mi> </mrow> <mrow> <mi>g</mi> </mrow> <mrow> <mn>1</mn> </mrow> </msubsup> </mrow> </math> </span></p>

Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <msubsup> <mrow> <mi>t</mi> </mrow> <mrow> <mn>2</mn> <mi>g</mi> </mrow> <mrow> <mn>6</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>e</mi> </mrow> <mrow> <mi>g</mi> </mrow> <mrow> <mn>0</mn> </mrow> </msubsup> </mrow> </math> </span></p>

Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <msubsup> <mrow> <mi>t</mi> </mrow> <mrow> <mn>2</mn> <mi>g</mi> </mrow> <mrow> <mn>5</mn> </mrow> </msubsup> <msubsup> <mrow> <mi>e</mi> </mrow> <mrow> <mi>g</mi> </mrow> <mrow> <mn>1</mn> </mrow> </msubsup> </mrow> </math> </span></p>

2 Views|Posted 4 months ago

Asked by Shiksha User

1 Answer

Sort by:

V

Answered by

Vishal Baghel | Contributor-Level 10

4 months ago

Correct Option - 3

Detailed Solution:

${[C o {(N H_{3})}_{6}]}^{3 +}, N H_{3}$ becomes strong ligand due to +3 oxidation state of cobalt ion. Hence electronic configuration of CO³⁺ is $t_{2 g}^{6} e_{g}^{0}$

Upvote

Thumbs Down Icon

Similar Questions for you

At 25°C the standard emf of cell having reactions involving two electrons change is found to be 0.295 V. The equilibrium constant of the reaction is :

Alok Kumar Singh

ΔG° = –RT * 2.303 log K

–nFE° = +RT * 2.303 log K

2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log₁₀ K

10 = log₁₀ K = 1010

Kindly consider the following

Alok Kumar Singh

It has chiral centre and differently di substituted double bonded carbon atoms.

Which of the following will not give ether as product :-

Alok Kumar Singh

Which is most reactive towards electrophilic aromatic substitution reaction :-

Alok Kumar Singh

Rate of ESR ∝ No. of α – H (Hyperconjugation)

Which one of the following ions is the most stable in aqueous solution ?

(At. No. Ti = 22, V = 23, Cr = 24, Mn=25)

Alok Kumar Singh

Cr³⁺ion is a most stable in aqueous solution due to. t_2g half filled configuration

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K

Colleges

|

1.2K

Exams

|

6.9L

Reviews

|

1.8M

Answers

Learn more about...

Chemistry Coordination Compounds 2025

Chemistry Coordination Compounds 2025

View Exam Details

Most viewed information

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Quick Actions

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Have a question related to your career & education?

or

See what others like you are asking & answering