Describe hybridisation in the case of PCl5 and SF6. The axial bonds are longer as compared to equatorial bonds in PCl5 whereas in SF6
both axial bonds and equatorial bonds have the same bond length. Explain.
Describe hybridisation in the case of PCl5 and SF6. The axial bonds are longer as compared to equatorial bonds in PCl5 whereas in SF6 both axial bonds and equatorial bonds have the same bond length. Explain.
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1 Answer
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This is a Long Answer Type Questions as classified in NCERT Exemplar
Ans: Hybridisation in the case of PCl5 :
The hybridisation of phosphorus PCl5 is sp3d and it has a trigonal bipyramidal geometry. The axial bonds in PCl5 are slightly longer as compared to the equatorial bonds because axial bonds experience greater repulsive forces from other bonds as compared to the equatorial bonds.
Hybridisation in the case of SF6:
The hybridisation of sulphur in SF6 is sp3d2 and the molecule has an octahedral geometry. The bond length of axial as well as the equatorial bonds are similar because all the bonds in octahedral geometry experience similar r
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