Diamond has a three dimensional structure of C atoms formed by covalent bonds. The structure of diamond has face centre cubic lattice where 50% of the tetrahedral voids are also occupied by carbon atoms. The number of carbon atoms present per unit cell of diamond is_________.
Diamond has a three dimensional structure of C atoms formed by covalent bonds. The structure of diamond has face centre cubic lattice where 50% of the tetrahedral voids are also occupied by carbon atoms. The number of carbon atoms present per unit cell of diamond is_________.
In fcc structure of diamond four C present in fcc lattice and other four C present in tetrahedral voids where 50% of tetrahedral voids are occupied. Hence number of carbon atoms present per unit cell of diamond is 8.
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ΔG° = –RT * 2.303 log K
–nFE° = +RT * 2.303 log K
2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K
10 = log10 K = 1010
It has chiral centre and differently di substituted double bonded carbon atoms.
For FCC lattice
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CsCl has BCC structure in which Cl– is present at corners of cube and Cs+ at body centre
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Chemistry Ncert Solutions Class 12th 2023
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