Dihydrogen reacts with CuO to give

$l^{-}+H_2{O}_2+2H^{+}\to l_2+2H_{2}O$

(-1) oxidation (0)

Here, I is reducing agent

${}_{}$ $\therefore H_2{O}_2$  behaves like oxidizing agent

In reducing action, H₂O₂ changes to O₂ because it will oxides but option (A) is in acidic medium, hence answer will be (C).

Urea acts as negative catalyst for decomposition of H₂O₂.

Tritium is radioactive and it decays into He³ during emission of β-radiation

₁T³ → ₂He³ + _-1e⁰

Higher the E.N. difference between hydrogen and other atom then higher be the strength of intermolecular H-bond

Here, order of difference in E.N is

O - H > N – H > C - H

Hence, correct order of H bond strength is,

CH₄ < HCN < NH₃