Enthalpy of neutralisation of CH3COOH by NaOH is – 50.6 kJ/mol and the heat of neutralisation of a strong acid with NaOH is – 55.9 kJ/mol. The value of ΔH for the ionisation of CH3COOH is :
Enthalpy of neutralisation of CH3COOH by NaOH is – 50.6 kJ/mol and the heat of neutralisation of a strong acid with NaOH is – 55.9 kJ/mol. The value of ΔH for the ionisation of CH3COOH is :
Option 1 -
3.5 kJ / mol
Option 2 -
4.6 kJ / mol
Option 3 -
5.3 kJ / mol
Option 4 -
6.4 kJ / mol
Asked by Shiksha User
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1 Answer
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Correct Option - 3
Detailed Solution:CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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