For a certain first order reaction 32% of the reactant is left after 570s. The rate constant of this reaction is _______ ×10⁻³ s⁻¹. (Round off to the nearest integer).
[Given: log₁₀2 = 0.301, ln10 = 2.303]
For a certain first order reaction 32% of the reactant is left after 570s. The rate constant of this reaction is _______ ×10⁻³ s⁻¹. (Round off to the nearest integer).
[Given: log₁₀2 = 0.301, ln10 = 2.303]
Asked by Shiksha User
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1 Answer
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Kt = 2.303 log? (A? /A? )
K × 570 = 2.303 log? (100/32)
K = [2.303 / 570] [log?10² - log?2? ]
K = [2.303 / 570] [2 - 5 × 0.301] = [2.303 / 570] × 0.495 = 0.002 = 2.0 × 10? ³ s? ¹
Ans = 2
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