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For a d⁴ metal ion in an octahedral field, the correct electronic configuration is

Option 1 -

t₂g³e¹g when Δₒ < P

Option 2 -

t₂g⁴e⁰g when Δₒ > P

Option 3 -

t₂g³e¹g when Δₒ > P

Option 4 -

t₂g²e²g when Δₒ

0 3 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 1


    Detailed Solution:

    For d? configuration if Δ? < P the electronic configuration is t? g³ e¹g


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