Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven Chemistry Chemical Kinetics Class 12th Chemistry

For a first order reaction A®B, the rate constant, k = 5.5 * 10^-¹⁴s^-¹. The time required for 67% completion of reaction is x * 10^-¹ times the half life of reaction. The value of x is ________ (Nearest integer)

(Given : log 3 = 0.4771)

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Raj Pandey | Contributor-Level 9

4 months ago

Rate constant, k = 5.5 * 10^-14 s^-1.

$t = \frac{2.303}{k} l o g \frac{{[R]}_{0}}{[R]}$

= $\frac{2.303}{k} l o g 3 - (i)$

$t_{50 %} = \frac{2.303}{k} l o g 2 - (i i)$

From (i) & (ii)

$\frac{t_{67 %}}{t_{50 %}} = \frac{l o g 3}{l o g 2}$

= 1.58 t_50%

So; t_67%is 15.8 * 10^-1 times half life.

X = 16 (the nearest integer)

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Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven 2025

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