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For a first order reaction, the time required for completion of 90% reaction is ‘x’ times the half life of the reaction. The value of ‘x’ is

(Given : In 10 = 2.303 and log 2 = 0.3010)

Option 1 -

1.12

Option 2 -

2.43

Option 3 -

3.32

Option 4 -

33.31

0 3 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    2 months ago
    Correct Option - 3


    Detailed Solution:

    T 9 0 % = 2 . 3 0 3 k l o g 1 0 0 1 0

    T 5 0 % = 2 . 3 0 3 k l o g 1 0 0 5 0

    T 9 0 % T 5 0 % = l o g 1 0 l o g 2 = 1 0 . 3 0 1 = 3 . 3 2

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