For an ideal gas, the work of reversible expansion under isothermal condition can be calculated by using the expression w= -nRTln V f V i

A sample containing 1.0 mol of an ideal gas is expanded isothermally and reversibly to ten times of its original volume, in two separate experiments. The expansion is carried out at 300 K and at 600 K respectively. Choose the correct option.

(i) Work done at 600 K is 20 times the work done at 300 K.

(ii) Work done at 300 K is twice the work done at 600 K.

(iii) Work done at 600 K is twice the work done at 300 K.

(iv) ∆U = 0 in both cases.

16 Views|Posted 8 months ago
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1 Answer
A
8 months ago

This is a Multiple Choice Questions as classified in NCERT Exemplar

option (iv)

For
isothermal reversible change

q= -w = nRTln V f V i  =2.303nRTlog

W 600 k W 300 k = 1 * R * 600 K l n 10 1 1 * R * 300 K l n 10 1 = 600 300  =2

For
isothermal expansion of ideal gases,  ? U = 0

Since,
temperature is constant this means there is no change in internal energy.

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Chemistry NCERT Exemplar Solutions Class 11th Chapter Six 2025

Chemistry NCERT Exemplar Solutions Class 11th Chapter Six 2025

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