For combustion of one mole of magnesium in an open container at 300 K and1 bar pressure, $Δ_{C} H^{Θ} = - 601.70 k J m o l^{- 1},$ the magnitude of change in internal energy for the reaction is__________ kJ. (Nearest integer)

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Alok Kumar Singh | Contributor-Level 10

6 months ago

For combustion of Mg:

Mg (s) + $\frac{1}{2} O_{2} (g) \to M g O (s)$

Here, $Δ n g = - \frac{1}{2}$

Now using

$Δ H = Δ U + Δ n g R T$

-601.7 = $Δ U + (- \frac{1}{2}) * 8.3 * 1 0^{- 3} * 300$

$Δ U = - 600.45 k J$

So; magnitude of $Δ U$ is 600 kJ (the nearest integer).

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For combustion of one mole of magnesium in an open container at 300 K and1 bar pressure, Δ C H Θ = − 6 0 1 . 7 0 k J m o l − 1 , the magnitude of change in internal energy for the reaction is__________ kJ. (Nearest integer)

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