For the first order reaction A → 2B, 1 mole of reactant A gives 0.2 moles of B after 100 minutes. The half life of the reaction is _____ min. (Round off to the Nearest Integer).
[Use : ln2 = 0.69, ln 10 = 2.3 Properties of logarithms : ln x? = y ln x; ln(x/y) = lnx – lny ]
For the first order reaction A → 2B, 1 mole of reactant A gives 0.2 moles of B after 100 minutes. The half life of the reaction is _____ min. (Round off to the Nearest Integer).
[Use : ln2 = 0.69, ln 10 = 2.3 Properties of logarithms : ln x? = y ln x; ln(x/y) = lnx – lny ]
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1 Answer
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A → 2B
t = 0: 1 mole 0
after 100 min: (1 - 0.1) mol 0.2 mol
K = (1/t)ln [a/ (a-n)]
K = (2.303/100)log (1/0.9) min? ¹
0.693/t? /? = (2.303/100) [log10 - log9] = (2.303/100) x 0.046
t? /? = 69.3 / (2.303 x 0.046) = 654.15 min
Ans. = 654 (the nearest integer)
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