For the given first order reaction

A -> B

The half life of the reaction is 0.3010 min. The ration of the initial concentration of reactant to the concentration of reactant at time 2.0 min will be equal to________________. (Nearest integer)

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Answered by

Vishal Baghel | Contributor-Level 10

2 months ago

t1/2 = 0.301 min

t = 2 min

$K = \frac{2.303}{t} l o g (\frac{C o}{C t})$

$\frac{0.693}{0.301} = \frac{2.303}{2} l o g (\frac{C o}{C t})$

$\frac{2.303 \times 0.301}{0.301} = \frac{2.303}{2} l o g (\frac{C o}{C t})$

$∴ 2 = l o g (\frac{C o}{C t})$

$\frac{C o}{C t} = 1 0^{2} = 100$

Ans. 100

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For the given first order reaction

A -> B

The half life of the reaction is 0.3010 min. The ration of the initial concentration of reactant to the concentration of reactant at time 2.0 min will be equal to________________. (Nearest integer)

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For the given first order reaction A -> B The half life of the reaction is 0.3010 min. The ration of the initial concentration of reactant to the concentration of reactant at time 2.0 min will be equal to________________. (Nearest integer)

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For the given first order reaction

A -> B

The half life of the reaction is 0.3010 min. The ration of the initial concentration of reactant to the concentration of reactant at time 2.0 min will be equal to________________. (Nearest integer)