For the given reactions

Sn² + 2e^- ® Sn

Sn⁴ + 4e^- ® Sn

The electrode potentials are ; $E_{S{n}^{2+}/Sn}^o$ = -0.140V and $E_{S{n}^{4+}/Sn}^o=0.010V.$ The magnitude of standard electrode potential for Sn⁴⁺ / Sn²⁺ i.e. $E_{S{n}^{4+}/S{n}^{2+}}^o$  is ___________ * 10^-2 V. (Nearest integer)

$E_{S{n}^{2+}/Sn}^0=-0.140V=E_2^0$

$E_{S{n}^{4+}/Sn}^0=+0.010V=E_3^0$

Here, $\Delta G_3^0=\Delta G_1^0+\Delta G_2^0$

$-4F{E}_3^0=-2F{E}_1^0-2F{E}_2^0$

$E_3^0=\frac{E_1^0+E_2^0}{2}$

$+0.010=\frac{E_1^0+\left(-0.140\right)}{2}$

$E_1^0=E_{S{n}^{4+}/S{n}^{2+}}^0=+0.16$

= 16 * 10^-2 V