Given below are two statements:

  Statement I : ${\left[Ni{\left(CN\right)}_4\right]}^{2-}$  is square planar and diamagnetic complex, with dsp² hybridizatin for Ni but $\left[Ni{\left(CO\right)}_4\right]$  is tetrahedral, paramagnetic and with sp³ hybridization for Ni.

Statement II :  ${\left[NiC{l}_4\right]}^{2-}and\left[Ni{\left(CO\right)}_4\right]$  both have same d-electron configuration have same geometry and are paramagnetic.

In light the above statements, choose the correct answer from the options given below:

 

Correct Option - 4


Detailed Solution:

${\left[Ni{\left(CN\right)}_4\right]}^{2-}$  

CN^- is strong field ligand

$N{i}^{2+}=4s^{0}3d^8$  

 Here; ${\left[Ni{\left(CN\right)}_4\right]}^{2-}$ is square planar and diamagnetic.

$\left[Ni{\left(CO\right)}_4\right]$  

Ni = 4s²3d⁸         Co is strong field ligand.

Here ;  $\left[Ni{\left(CO\right)}_4\right]$  is tetrahedral and diamagnetic

${\left[Ni{\left(CN\right)}_4\right]}^{2-}$  has 3d⁸ configuration while $\left[Ni{\left(CO\right)}_4\right]$  has 3d¹⁰ configuration.

<p><span contenteditable="false"> <math> <mrow> <msup> <mrow> <mrow> <mo> [</mo> <mrow> <mi>N</mi> <mi>i</mi> <msub> <mrow> <mrow> <mo> (</mo> <mrow> <mi>C</mi> <mi>N</mi> </mrow> <mo>)</mo> </mrow> </mrow> <mrow> <mn>4</mn> </mrow> </msub> </mrow> <mo>]</mo> </mrow> </mrow> <mrow> <mn>2</mn> <mo>−</mo> </mrow> </msup> </mrow> </math> </span>&nbsp;</p><p>CN^- is strong field ligand</p><p><br><span contenteditable="false"> <math> <mrow> <mi>N</mi> <msup> <mrow> <mi>i</mi> </mrow> <mrow> <mn>2</mn> <mo>+</mo> </mrow> </msup> <mo>=</mo> <mn>4</mn> <msup> <mrow> <mi>s</mi> </mrow> <mrow> <mn>0</mn> </mrow> </msup> <mn>3</mn> <msup> <mrow> <mi>d</mi> </mrow> <mrow> <mn>8</mn> </mrow> </msup> </mrow> </math> </span>&nbsp;</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1757933166php3oK8k3.jpeg" alt="" width="410" height="151" loading="lazy"></picture></div></div><p>&lt;!- [endif]-&gt;</p><p>&nbsp;Here; <span contenteditable="false"> <math> <mrow> <msup> <mrow> <mrow> <mo> [</mo> <mrow> <mi>N</mi> <mi>i</mi> <msub> <mrow> <mrow> <mo> (</mo> <mrow> <mi>C</mi> <mi>N</mi> </mrow> <mo>)</mo> </mrow> </mrow> <mrow> <mn>4</mn> </mrow> </msub> </mrow> <mo>]</mo> </mrow> </mrow> <mrow> <mn>2</mn> <mo>−</mo> </mrow> </msup> </mrow> </math> </span>is square planar and diamagnetic.</p><p><span contenteditable="false"> <math> <mrow> <mrow> <mo> [</mo> <mrow> <mi>N</mi> <mi>i</mi> <msub> <mrow> <mrow> <mo> (</mo> <mrow> <mi>C</mi> <mi>O</mi> </mrow> <mo>)</mo> </mrow> </mrow> <mrow> <mn>4</mn> </mrow> </msub> </mrow> <mo>]</mo> </mrow> </mrow> </math> </span>&nbsp;</p><p>Ni = 4s²3d⁸&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; Co is strong field ligand.</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1757933230phpv74Bho.jpeg" alt="" width="486" height="145" loading="lazy"></picture></div></div><p>Here ;&nbsp;<span contenteditable="false"> <math> <mrow> <mrow> <mo> [</mo> <mrow> <mi>N</mi> <mi>i</mi> <msub> <mrow> <mrow> <mo> (</mo> <mrow> <mi>C</mi> <mi>O</mi> </mrow> <mo>)</mo> </mrow> </mrow> <mrow> <mn>4</mn> </mrow> </msub> </mrow> <mo>]</mo> </mrow> </mrow> </math> </span>&nbsp;is tetrahedral and diamagnetic</p><p><span contenteditable="false"> <math> <mrow> <msup> <mrow> <mrow> <mo> [</mo> <mrow> <mi>N</mi> <mi>i</mi> <msub> <mrow> <mrow> <mo> (</mo> <mrow> <mi>C</mi> <mi>N</mi> </mrow> <mo>)</mo> </mrow> </mrow> <mrow> <mn>4</mn> </mrow> </msub> </mrow> <mo>]</mo> </mrow> </mrow> <mrow> <mn>2</mn> <mo>−</mo> </mrow> </msup> </mrow> </math> </span>&nbsp;has 3d⁸ configuration while <span contenteditable="false"> <math> <mrow> <mrow> <mo> [</mo> <mrow> <mi>N</mi> <mi>i</mi> <msub> <mrow> <mrow> <mo> (</mo> <mrow> <mi>C</mi> <mi>O</mi> </mrow> <mo>)</mo> </mrow> </mrow> <mrow> <mn>4</mn> </mrow> </msub> </mrow> <mo>]</mo> </mrow> </mrow> </math> </span>&nbsp;has 3d¹⁰ configuration.</p>

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