Given below are two statements:
Statement I:
The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association in aldehydes and ketones due to dipole-dipole interactions.
Statement II:
The boiling points of aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of H-bonding.
In the light of the above statements, choose the most appropriate answer from the options given below:
Given below are two statements:
Statement I:
The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association in aldehydes and ketones due to dipole-dipole interactions.
Statement II:
The boiling points of aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of H-bonding.
In the light of the above statements, choose the most appropriate answer from the options given below:
Option 1 -
Both Statement I and Statement II are correct
Option 2 -
Both Statement I and Statement II are incorrect.
Option 3 -
Statement I is correct but Statement II is incorrect.
Option 4 -
Statement I is incorrect but Statement II is correct.
-
1 Answer
-
Correct Option - 4
Detailed Solution:As compared to hydrocarbons of similar mass aldehydes and ketones will have greater dipole-dipole interactions.
Similar Questions for you
CH3—CH2—CHO does not undergo Cannizzaro reaction because it has α-hydrogen.
Acetaldehyde (CH3CHO) gives positive lodoform test and positive Fehling's solution test
CH3—CH2—CHO does not undergo Cannizzaro reaction because it has α-hydrogen.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers