Given below are two statements.

Statements I: Maltose has two a-D-glucose units linked at C₁ and C₄ and is a reducing sugar:

Statements II: Maltose has two manosaccharides: a-D-glucose and b-D-glucose linked at C₁ and C₆ and its is a non-reducing sugar.

In the light of the above statements, choose the correct answer from the options given below.

Correct Option - 3


Detailed Solution:

$C_{12}{H}_{22}{O}_{11}+H_{2}O\to \alpha -D-glucose+\alpha -D-glucose$

In maltose, two units of a-D-glucose are linked by glycosidic linkage at C₁ and C₄ as shown.

    

a - D – glucose                              a - D - glucose

Maltose has hemiacetal link so it is reducing sugar.

<p><span contenteditable="false"> <math> <mrow> <msub> <mrow> <mi>C</mi> </mrow> <mrow> <mn>1</mn> <mn>2</mn> </mrow> </msub> <msub> <mrow> <mi>H</mi> </mrow> <mrow> <mn>2</mn> <mn>2</mn> </mrow> </msub> <msub> <mrow> <mi>O</mi> </mrow> <mrow> <mn>1</mn> <mn>1</mn> </mrow> </msub> <mo>+</mo> <msub> <mrow> <mi>H</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mi>O</mi> <mo>→</mo> <mi>α</mi> <mo>−</mo> <mi>D</mi> <mo>−</mo> <mi>g</mi> <mi>l</mi> <mi>u</mi> <mi>c</mi> <mi>o</mi> <mi>s</mi> <mi>e</mi> <mo>+</mo> <mi>α</mi> <mo>−</mo> <mi>D</mi> <mo>−</mo> <mi>g</mi> <mi>l</mi> <mi>u</mi> <mi>c</mi> <mi>o</mi> <mi>s</mi> <mi>e</mi> </mrow> </math> </span></p><p>In maltose, two units of a-D-glucose are linked by glycosidic linkage at C₁ and C₄ as shown.</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1752037246phpTOOHVg.jpeg" alt="" width="342" height="165" loading="lazy"></picture>&nbsp; &nbsp;&nbsp;</div></div><p>a - D – glucose&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; a - D - glucose</p><p>Maltose has hemiacetal link so it is reducing sugar.</p>

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