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Given K n e t = K 1 K 2 K 3  when E a 1 =40 kJ/mol

  E a 1 =50 kJ/mol. = E a 1 60 kJ/mol

Calculate value of (Ea)net in kJ/mol

0 1 View | Posted 2 weeks ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    2 weeks ago

    (Ea)net = E a 1 + E a 2 – E a 3  

    = 40 + 50 – 60

    = 90 – 60

    = 30kJ/mol

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