How much propyl alcohol must be added to 1.00lt. of water so the solution will not freeze at –15°C ? (K_f of water = 1.86 KKgmol-1)[d(H2O) = 1 g/ml and molecular mass of propyl alcohol = 60 g/mol ]

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States of Matter Ncert Solutions Chemistry Class 11th Chemistry Class 11th

How much propyl alcohol must be added to 1.00lt. of water so the solution will not freeze at –15°C ? (K_f of water = 1.86 KKgmol^-1)[d(H₂O) = 1 g/ml and molecular mass of propyl alcohol = 60 g/mol ]

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Answered by

Vishal Baghel | Contributor-Level 10

4 weeks ago

From ΔT? = K? × m, and ΔT? = 15°C
∴ m = ΔT? / K? = 15 / 1.86 = 8.06
So the amount of propyl alcohol to be added.
= m × molwt = 8.06 × 60 = 483.6 g

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