How will you account for the 104.5° bond angle in water?
How will you account for the 104.5° bond angle in water?
This is a short answer type question as classified in NCERT Exemplar
In water hybridisation of oxygen is sp3. Angle should be109o (approx.) but due to LP - LP repulsion bond angle reduces to 104.5°.
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H2S has minimum boiling point.
PbS + 4H2O2->PbSO4 + 4H2O.
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HF molecules are associated with strong intermolecular hydrogen bonding hence its boiling point is the highest
Compound Melting Point (K)
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Chemistry NCERT Exemplar Solutions Class 11th Chapter Nine 2025
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