Identify the incorrect statement from the options below for the above cell:

Option 1 - <p>If Eext &lt; 1.1 V, Zn dissolves at anode and Cu deposits at cathode<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 2 - <p>If Eext = 1.1 V, no flow of e¯or current occurs<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 3 - <p>If Eext &gt; 1.1 V, Zn dissolves at Zn electrode and Cu deposits at Cu electrode<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 4 - <p>If Eext &gt; 1.1 V, e¯flows from Cu to Zn<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
3 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
R
5 months ago
Correct Option - 3
Detailed Solution:

Eext > 1.1 V, cell reaction is reversed
i.e. Cu → Cu²? anode
Zn²? + 2e? → Zn cathode

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Chemistry Electrochemistry 2025

Chemistry Electrochemistry 2025

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