If 4 g of NaOH dissolves in 36 g of H₂O, calculate the mole fraction of each component in the solution. Also, determine the molarity of solution (specific gravity of solution is 1g mL^–1).

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alok kumar singh | Contributor-Level 10

3 months ago

This is a Short Answer Type Questions as classified in NCERT Exemplar

Molar mass of NaOH = 40 g/ mole

Molar mass of water =18 g / mole

Mass of NaOH= 4 g

Number of moles of 4 g NaOH = $\frac{4 g}{40 g}$ = 0.1 mol

Number of moles of H₂O= $\frac{36 g}{18 g}$ =2 mol

Mole fraction of water

$\frac{26 g}{N u m b e r o f m o l e s o f N a O H + N u m b e r o f m o l e s o f H_{2} O}$

Mole fraction of NaOH = $\frac{2 g}{0.1 + 2 g}$ = $\frac{2 g}{2.1 g}$ = 0.95

Number of moles of= $\frac{2 g}{0.1 g}$ = $\frac{0.1 g}{2.1 g}$ = 0.047

Number of moles of NaOH

Mass of solution = Mass of solute + Mass of solvent

Mass of NaOH + Mass of water 4 g + 36 g = 40 g

Specific gravity of solution =1 g / ml

1 litre =1000 ml volume of solution = 40ml

40ml = 0.04 litre

Molarity = $\frac{n u m b e r o f m o l e s o f s o l u t e}{V o l u m e i n l i t r e}$ = $\frac{0.1 m o l}{0.04 l i t r e}$ = 2.5M

This is a Short Answer Type Questions as classified in NCERT ExemplarMolar mass of NaOH = 40 g/ moleMolar mass of water =18 g / moleMass of NaOH= 4 gNumber of moles of 4 g NaOH = <math> <mfrac> <mrow> <mrow> <mn>4</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> </mrow> </mrow> <mrow> <mrow> <mn>40</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math> = 0.1 molNumber of moles of H2O= <math> <mfrac> <mrow> <mrow> <mn>36</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> </mrow> </mrow> <mrow> <mrow> <mn>18</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math> =2 molMole fraction of water <math> <mfrac> <mrow> <mrow> <mn>26</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> </mrow> </mrow> <mrow> <mrow> <mi mathvariant="normal">N</mi> <mi mathvariant="normal">u</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">b</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">f</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">l</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">f</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">N</mi> <mi mathvariant="normal">a</mi> <mi mathvariant="normal">O</mi> <mi mathvariant="normal">H</mi> <mo>+</mo> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">N</mi> <mi mathvariant="normal">u</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">b</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">f</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">l</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">f</mi> <mi mathvariant="normal"> </mi> <msub> <mrow> <mrow> <mi mathvariant="normal">H</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msub> <mi mathvariant="normal">O</mi> </mrow> </mrow> </mfrac> </math> Mole fraction of NaOH = <math> <mfrac> <mrow> <mrow> <mn>2</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> </mrow> </mrow> <mrow> <mrow> <mn>0.1</mn> <mi mathvariant="normal"> </mi> <mo>+</mo> <mi mathvariant="normal"> </mi> <mn>2</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math>  = <math> <mfrac> <mrow> <mrow> <mn>2</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> </mrow> </mrow> <mrow> <mrow> <mn>2.1</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math>  = 0.95Number of moles of= <math> <mfrac> <mrow> <mrow> <mn>2</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> </mrow> </mrow> <mrow> <mrow> <mn>0.1</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math>  = <math> <mfrac> <mrow> <mrow> <mn>0.1</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> </mrow> </mrow> <mrow> <mrow> <mn>2.1</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">g</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math> = 0.047Number of moles of NaOHMass of solution = Mass of solute + Mass of solventMass of NaOH + Mass of water 4 g + 36 g = 40 gSpecific gravity of solution =1 g / ml1 litre =1000 ml volume of solution = 40ml40ml = 0.04 litreMolarity = <math> <mfrac> <mrow> <mrow> <mi mathvariant="normal">n</mi> <mi mathvariant="normal">u</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">b</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">f</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">l</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">f</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">s</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">l</mi> <mi mathvariant="normal">u</mi> <mi mathvariant="normal">t</mi> <mi mathvariant="normal">e</mi> </mrow> </mrow> <mrow> <mrow> <mi mathvariant="normal">V</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">l</mi> <mi mathvariant="normal">u</mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">i</mi> <mi mathvariant="normal">n</mi> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">l</mi> <mi mathvariant="normal">i</mi> <mi mathvariant="normal">t</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal">e</mi> </mrow> </mrow> </mfrac> </math> = <math> <mfrac> <mrow> <mrow> <mn>0.1</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">m</mi> <mi mathvariant="normal">o</mi> <mi mathvariant="normal">l</mi> </mrow> </mrow> <mrow> <mrow> <mn>0.04</mn> <mi mathvariant="normal"> </mi> <mi mathvariant="normal">l</mi> <mi mathvariant="normal">i</mi> <mi mathvariant="normal">t</mi> <mi mathvariant="normal">r</mi> <mi mathvariant="normal">e</mi> <mi mathvariant="normal"> </mi> </mrow> </mrow> </mfrac> </math> = 2.5M

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If 4 g of NaOH dissolves in 36 g of H₂O, calculate the mole fraction of each component in the solution. Also, determine the molarity of solution (specific gravity of solution is 1g mL^–1).

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If 4 g of NaOH dissolves in 36 g of H2O, calculate the mole fraction of each component in the solution. Also, determine the molarity of solution (specific gravity of solution is 1g mL–1).

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If 4 g of NaOH dissolves in 36 g of H₂O, calculate the mole fraction of each component in the solution. Also, determine the molarity of solution (specific gravity of solution is 1g mL^–1).