If ionisation energy of an element is as follows :

X → X+ + 1e; 1E1 = x kJ/mol

X+ → X2+ + 1e ; 1E2 = 1.5 x kJ/mol

X2+ → X3+ + 1e ; IE3 = 15x kJ/mol

This   element   may   have    the    electronic configuration :-

Option 1 - <p>ns<sup>1</sup></p>
Option 2 - <p>ns<sup>2</sup></p>
Option 3 - <p>ns<sup>2</sup> np<sup>4</sup></p>
Option 4 - <p>ns<sup>2</sup> np<sup>3</sup></p>
1 Views|Posted 4 months ago
Asked by Shiksha User
1 Answer
A
4 months ago
Correct Option - 2
Detailed Solution:

A jump is seen after 2nd Ip so Ve = 2

hence configuration would be ns2

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Chemistry Ncert Solutions Class 12th 2023

Chemistry Ncert Solutions Class 12th 2023

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