If ionisation energy of an element is as follows :
X → X+ + 1e–; 1E1 = x kJ/mol
X+ → X2+ + 1e– ; 1E2 = 1.5 x kJ/mol
X2+ → X3+ + 1e– ; IE3 = 15x kJ/mol
This element may have the electronic configuration :-
If ionisation energy of an element is as follows :
X → X+ + 1e–; 1E1 = x kJ/mol
X+ → X2+ + 1e– ; 1E2 = 1.5 x kJ/mol
X2+ → X3+ + 1e– ; IE3 = 15x kJ/mol
This element may have the electronic configuration :-
Option 1 -
ns1
Option 2 -
ns2
Option 3 -
ns2 np4
Option 4 -
ns2 np3
Asked by Shiksha User
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1 Answer
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Correct Option - 2
Detailed Solution:A jump is seen after 2nd Ip so Ve– = 2
hence configuration would be ns2
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