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In Freundlich adsorption isotherm, slope of AB line is:

 

Option 1 -

1 n w i t h ( 1 n = 0     t o     1 )

Option 2 -

log n with (n > 1)

Option 3 -

l o g 1 n w i t h ( n < 1 )

Option 4 -

n with (n, 0.1 to 0.5)

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 1


    Detailed Solution:

    Freundlich adsorption isotherm

      x m = k p 1 / n          

    l o g x m = 1 n l o g p + l o g k           

    Comparing with y = mx + C

    so, slope of given graph is  1 n  whose value varies from 0 to 1.

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