Class 12th Chemistry Ncert Solutions Chemistry Class 12th Surface Chemistry

In Freundlich adsorption isotherm, slope of AB line is:

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mi>n</mi> </mrow> </mfrac> <mi>w</mi> <mi>i</mi> <mi>t</mi> <mi>h</mi> <mrow> <mo>(</mo> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mi>n</mi> </mrow> </mfrac> <mo>=</mo> <mn>0</mn> <mtext> </mtext> <mtext> </mtext> <mi>t</mi> <mi>o</mi> <mtext> </mtext> <mtext> </mtext> <mn>1</mn> </mrow> <mo>)</mo> </mrow> </mrow> </math> </span></p>

Option 2 - <p>log n with (n > 1)</p>

Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>l</mi> <mi>o</mi> <mi>g</mi> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mi>n</mi> </mrow> </mfrac> <mi>w</mi> <mi>i</mi> <mi>t</mi> <mi>h</mi> <mrow> <mo>(</mo> <mrow> <mi>n</mi> <mo><</mo> <mn>1</mn> </mrow> <mo>)</mo> </mrow> </mrow> </math> </span></p>

Option 4 - <p>n with (n, 0.1 to 0.5)</p>

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Answered by

Vishal Baghel | Contributor-Level 10

4 months ago

Correct Option - 3

Detailed Solution:

Freundlich adsorption isotherm

$\frac{x}{m} = k p^{1 / n}$

$l o g \frac{x}{m} = \frac{1}{n} l o g p + l o g k$

Comparing with y = mx + C

so, slope of given graph is $\frac{1}{n}$ $\frac{}{}$ whose value varies from 0 to 1.

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Chemistry Ncert Solutions Class 12th 2023

Chemistry Ncert Solutions Class 12th 2023

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