In Friedel-Crafts alkylation of aniline, one gets

Option 1 -

alkylated product with ortho and para substitution.

Option 2 -

secondary amine after acidic treatment

Option 3 -

an amide product.         

Option 4 -

Positively charged nitrogen at benzene ring.

0 2 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago
    Correct Option - 4


    Detailed Solution:

     

    Aniline show acid-base reaction with AlCl3

    aniline is a Lewis base while AlCl3 acts as lewis acid.

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