In order to prepare a buffer solution of pH 5.74, sodium acetate is added to acetic acid. If the concentration of acetic acid in the buffer is 1.0 M, the concentration of sodium acetate in the buffer is _____ M. (Round off to the nearest integer).
[Given: pKa (acetic acid) = 4.74]
In order to prepare a buffer solution of pH 5.74, sodium acetate is added to acetic acid. If the concentration of acetic acid in the buffer is 1.0 M, the concentration of sodium acetate in the buffer is _____ M. (Round off to the nearest integer).
[Given: pKa (acetic acid) = 4.74]
-
1 Answer
-
For an acidic buffer solution, pH = pKa + log ( [Base]/ [Acid]).
Given pH = 5.74 and pKa = 4.74.
5.74 = 4.74 + log ( [Base]/1).
1 = log ( [Base]).
[Base] = 10M.
Similar Questions for you
ΔG° = –RT * 2.303 log K
–nFE° = +RT * 2.303 log K
2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K
10 = log10 K = 1010
It has chiral centre and differently di substituted double bonded carbon atoms.
For FCC lattice
Packing efficiency = 
CsCl has BCC structure in which Cl– is present at corners of cube and Cs+ at body centre
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 686k Reviews
- 1800k Answers

