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It is because of inability of ns2 electrons of the valence shell to participate in bonding that

Option 1 -

Sn2+ is oxidising while Pb4+ is reducing

Option 2 -

Sn2+ and Pb2+ are both oxidising and reducing

Option 3 -

Sn4+is reducing while Pb4+ is oxidising

Option 4 -

Sn2+ is reducing while Pb4+ is oxidising. 

0 2 Views | Posted a week ago
Asked by Shiksha User

  • 1 Answer

  • Correct Option - 4


    Detailed Solution:

    Heavier element of p block do not from pπ− pπ bonds as their atomic orbital are so large and diffius that they cannot have effecitve overlapping.

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