K₂Cr₂O₇ + H₂O₂ + H₂SO_{4 $\underset{conditions}{\overset{ether cold}{\to }}$} compound 'X' X is a chromium compound, what is the oxidation state of chromium in compound 'X'.

Correct Option - 1


Detailed Solution:

K₂Cr₂O₇ + H₂O₂ + H₂SO₄->  + K₂SO₄ + H₂O compound 'X' is ->CrO₅

Oxidation state of chromium = +6.

 

<p><span lang="EN-IN">K₂Cr₂O₇ + H₂O₂ + H₂SO₄-&gt;</span><span lang="EN-IN">&nbsp;&lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1820741007"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt;+ K₂SO₄ + H₂O compound 'X' is -&gt;</span><span lang="EN-IN">CrO₅</span></p><div class="photo-widget-full"><div class="figure"><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1759215336phpptfMZv.jpeg" alt="" width="172" height="123" loading="lazy"></picture></div><div class="figure"><p><span lang="EN-IN">Oxidation state of chromium = +6.</span></p></div></div><p>&nbsp;</p>

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