KBr is doped with 10⁻⁵ mole percent of SrBr₂. The number of cationic vacancies in 1 g of KBr crystal is ______ 10¹⁴. (Round off to the nearest integer).
[Atomic Mass: K: 39.1 u, Br: 79.9 u, NA = 6.023 *10²³]
KBr is doped with 10⁻⁵ mole percent of SrBr₂. The number of cationic vacancies in 1 g of KBr crystal is ______ 10¹⁴. (Round off to the nearest integer).
[Atomic Mass: K: 39.1 u, Br: 79.9 u, NA = 6.023 *10²³]
100 mol of KBr is doped with 10? mol of SrBr?
Therefore, 1 mol of KBr contains 10? mol of SrBr?
Molar mass of KBr = 119 g/mol .
119 g of KBr contains 10? mol of SrBr?
1 g of KBr contains (10? / 119) mol of SrBr?
Each Sr²? ion introduced creates one cation vacancy to maintain electrical neutrality.
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