Match List I with List II

Choose the correct answer from the options given below:

Correct Option - 1


Detailed Solution:

A. Phenol is converted to salicylaldehyde by Riemer-Tiemann reaction

                           

B. Phenol is converted to benzene using Zn powder

                          

C. Phenol is converted to benzoinone using oxidizing agent which is $N{a}_{2}C{r}_2{O}_7/H^{+}$

                           

D. Phenol can be converted to p-bromophenol using Br₂/CS₂           

           

...more

A. Phenol is converted to salicylaldehyde by Riemer-Tiemann reaction

                           

B. Phenol is converted to benzene using Zn powder

                          

C. Phenol is converted to benzoinone using oxidizing agent which is $N{a}_{2}C{r}_2{O}_7/H^{+}$

                           

D. Phenol can be converted to p-bromophenol using Br₂/CS₂           

                           

                          

less

<div class="photo-widget-full"><div class="figure"><p><strong>A. </strong>Phenol is converted to salicylaldehyde by Riemer-Tiemann reaction</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1752036281phpvL3qBy.jpeg" alt="" width="201" height="78" loading="lazy"></picture>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;</div></div><p><strong>B. </strong>Phenol is converted to benzene using Zn powder</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1752036306phpnl66oA.jpeg" alt="" width="168" height="92" loading="lazy"></picture>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;</div></div><p><strong>C.</strong> Phenol is converted to benzoinone using oxidizing agent which is <span contenteditable="false"> <math> <mrow> <mi>N</mi> <msub> <mrow> <mi>a</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <mi>C</mi> <msub> <mrow> <mi>r</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <msub> <mrow> <mi>O</mi> </mrow> <mrow> <mn>7</mn> </mrow> </msub> <mo>/</mo> <msup> <mrow> <mi>H</mi> </mrow> <mrow> <mo>+</mo> </mrow> </msup> </mrow> </math> </span>&lt;!- [if gte mso 9]>&lt;xml&gt; <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1813561808"> </o:OLEObject>&lt;/xml&gt;&lt;! [endif]-&gt;</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1752036320phpEVFqUc.jpeg" alt="" width="220" height="113" loading="lazy"></picture>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;</div></div><p><strong>D. </strong>Phenol can be converted to p-bromophenol using Br₂/CS_{2&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;}</p><div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1752036334phpBVDQ1v.jpeg" alt="" width="223" height="126" loading="lazy"></picture>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;</div></div>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;</div></div>

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