Match List – I with List – II.
List – I List – II
(A) Siderite (i) Cu
(B) Calamine (ii) Ca
(C) Malachite (iii) Fe
(D) Cryolite (iv) Al
(v) Zn
Choose the correct answer from the options given below:
Match List – I with List – II.
List – I List – II
(A) Siderite (i) Cu
(B) Calamine (ii) Ca
(C) Malachite (iii) Fe
(D) Cryolite (iv) Al
(v) Zn
Choose the correct answer from the options given below:
Option 1 -
(A) -> (i), (B) -> (ii), (C) -> (iii), (D) -> (iv)
Option 2 -
(A) -> (iii), (b) -> (v), (C) -> (i), (D) -> (iv)
Option 3 -
(A) -> (iii), (B) -> (i), (C) -> (v), (D) -> (ii)
Option 4 -
(A) -> (i), (B) -> (ii), (C) -> (v), (D) -> (iii)
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1 Answer
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Correct Option - 2
Detailed Solution:Siderite – FeCO3 (ore of iron)
Calamine – ZnCO3 (ore of zinc)
Malachite – CuCO3.Cu (OH)2 (ore of copper)
Cryolite – Na3AlF6 (ore of aluminium)
Similar Questions for you
Na+ C + N + S ®NaSCN
Fe3+ + SCN–
In the metallurgy of aluminium, purified Al2O3 is mixed with Na3AIF6 or CaF2 which lowers the melting point of the mixture and brings conductivity.
Ellingham diagram explains the feasibility of reduction process not the kinetics of process.
Malachite : CuCO3.Cu (OH)2
Azurite : 2CuCO3.Cu (OH)2
Cuprite : Cu2O
Copper pyrite : Cu2S.Fe2S3.
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