On the basis of thermochemical equations (a), (b) and (c), find out which of the algebric relationships given in options (i) to (iv) is correct.
(a) C (graphite) + O2 (g) → CO2 (g) ; ∆rH = x kJ/ mol
(b) C (graphite) + O2 (g) → CO (g) ; ∆rH = y kJ/ mol
(c) CO (g) + O2 (g) → CO2 (g) ; ∆rH = z kJ/ mol
(i) z = x + y
(ii) x = y – z
(iii) x = y + z
(iv) y = 2z – x
On the basis of thermochemical equations (a), (b) and (c), find out which of the algebric relationships given in options (i) to (iv) is correct.
(a) C (graphite) + O2 (g) → CO2 (g) ; ∆rH = x kJ/ mol
(b) C (graphite) + O2 (g) → CO (g) ; ∆rH = y kJ/ mol
(c) CO (g) + O2 (g) → CO2 (g) ; ∆rH = z kJ/ mol
(i) z = x + y
(ii) x = y – z
(iii) x = y + z
(iv) y = 2z – x
This is a Multiple Choice Questions as classified in NCERT Exemplar
option (iii)
When we add equations (b) and (c) we will get equation (a); hence, the Algebraic sum of y and z will give x, x =y + z.
Similar Questions for you
Kindly go through the solution
(1) [Ni (NH3)6]+2 → Ni+2 → d8, C. No. = 6,
SP3d2, Para
(2) [Co (H2O)6]+2 → Co+2 → d6, C. No. = 6
d2sp3, Dia
(3) [Ti (H2O)6]+3 → Ti+3 → d1, C. No. = 6
d2SP3, Para
(4) [Co (NH3)6]+3 → Co+3 → d5, C. No. = 6
d2sp3, Para
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...

Chemistry NCERT Exemplar Solutions Class 11th Chapter Six 2025
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering


