One mole ideal monoatomic gas is heated in two different processes according to path AB and AC. If temperature of state B and state C are equal. Calculate $\frac{q_{A C}}{q_{A B}}$

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alok kumar singh | Contributor-Level 10

2 months ago

$C_{v} = \frac{3 R}{2}$

AC polytropic P $\propto$ V

$\Rightarrow P . V^{- 1} = c o n s t a n t$

$C_{A C} = C_{V} + \frac{R}{1 - (- 1)} = 2 R$

AB isobaric

$C_{A B} = C_{P} = \frac{5 R}{2}$

$∴ \frac{Q_{A C}}{Q_{A B}} = \frac{C_{A C}}{C_{A B}} [? Δ T s a m e f o r b o t h]$

$= \frac{2 R}{(\frac{5 R}{2})} = \frac{4}{5} = 0.8$

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One mole ideal monoatomic gas is heated in two different processes according to path AB and AC. If temperature of state B and state C are equal. Calculate $\frac{q_{A C}}{q_{A B}}$

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One mole ideal monoatomic gas is heated in two different processes according to path AB and AC. If temperature of state B and state C are equal. Calculate q A C q A B

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One mole ideal monoatomic gas is heated in two different processes according to path AB and AC. If temperature of state B and state C are equal. Calculate $\frac{q_{A C}}{q_{A B}}$