One mole of any substance contains 6.022 × 1023 atoms/molecules. Number of molecules of H2SO4 present in 100 mL of 0.02M H2SO4 solution is ______
(i) 12.044 × 1020 molecules
(ii) 6.022 × 1023 molecules
(iii) 1 × 1023 molecules
(iv) 12.044 × 1023 molecules
One mole of any substance contains 6.022 × 1023 atoms/molecules. Number of molecules of H2SO4 present in 100 mL of 0.02M H2SO4 solution is ______
(i) 12.044 × 1020 molecules
(ii) 6.022 × 1023 molecules
(iii) 1 × 1023 molecules
(iv) 12.044 × 1023 molecules
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1 Answer
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This is a Multiple Choice Questions as classified in NCERT Exemplar
Option (A)The molarity (M) is given by the formula:
M
On substituting the values in the above equation:
0.02M =
n = 0.002 mol
The number of molecules can be calculated as, number of moles
=
On substituting the values in the above equation:
0.002 mol =
number of molecules = 0.002 6.022 1023
= 12.044 1020
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