Q 2.17 The vapour pressure of water is 12.3 kPa at 300 K. Calculate vapour pressure of 1 molal solution of a non-volatile solute in it.
Q 2.17 The vapour pressure of water is 12.3 kPa at 300 K. Calculate vapour pressure of 1 molal solution of a non-volatile solute in it.
Given: 1 molal solution means 1 mole of solute present in 1000g of water solvent)
Molecular weight of water = H2O = 1 * 2 + 16 = 18g/mol
No. of moles of water, n = given mass /molecular weight
⇒ n = 1000/18 = 55.56 gmol-1
Mole fraction of solute in solution, x2 = moles of solute/ (moles of solute + mole
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If a solution containing more than 0.9% salt is used, and we place blood cells in it, the water will flow out of the cells, and they will shrink. Such a solution is a hypertonic solution.
Similarly, if a solution contains less than 0.9% salt, the water will flow into the cells, and they will enlarge.
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