Q 2.20 A 5% solution (by mass) of cane sugar in water has freezing point of 271K. Calculate the freezing point of 5% glucose in water if freezing point of pure water is 273.15 K.
Q 2.20 A 5% solution (by mass) of cane sugar in water has freezing point of 271K. Calculate the freezing point of 5% glucose in water if freezing point of pure water is 273.15 K.
5% solution means 5g of cane sugar is present in 100g of solution
Freezing point of solution = 271k
Freezing point of pure water = 273.15k
Molar mass of cane sugar (C12H22O11) = 12 * 12 + 1 * 22 + 16 * 11 = 342g
Moles of cane sugar = mass/molar mass = 5/342
⇒ n = 0.0146mol
Molality of solution = moles of
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