Select the ion of minimum limiting molar conductivity in water at 298 K.
Select the ion of minimum limiting molar conductivity in water at 298 K.
Option 1 - <p>CH<sub>3</sub>COO<sup>-</sup></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>S</mi> <msubsup> <mrow> <mi>O</mi> </mrow> <mrow> <mn>4</mn> </mrow> <mrow> <mn>2</mn> <mo>−</mo> </mrow> </msubsup> </mrow> </math> </span></p>
Option 3 - <p>Cl<sup>-</sup></p>
Option 4 - <p>OH<sup>-</sup></p>
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Correct Option - 1
Detailed Solution:
Order of limiting molar conductivity
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ΔG° = –RT * 2.303 log K
–nFE° = +RT * 2.303 log K
2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K
10 = log10 K = 1010
It has chiral centre and differently di substituted double bonded carbon atoms.
Rate of ESR ∝ No. of α – H (Hyperconjugation)
Cr3+ion is a most stable in aqueous solution due to. t2g half filled configuration
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