Species having same bond order are :
(i) N2
(ii) N2–
(iii) F2+
(iv) O2–
Species having same bond order are :
(i) N2
(ii) N2–
(iii) F2+
(iv) O2–
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1 Answer
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This is a Multiple Choice Questions as classified in NCERT Exemplar
Ans: Option (iii) and (iv)
The formula of bond order is:
Bond order = ( Nb- Na)
Number of bonding and antibonding electrons can be found from the molecular electronic configuration of the species.
(i) Total number of electrons in N2 is 14. So, its molecular electronic configuration will be
σ1s2 σ∗1s2 σ2s2 σ∗2s2, π2p2x , π2p2y, s2pz2
The bond order will be:
( 10-4)= 3
(ii) The total number of electrons in N2 - is 15. So, its molecular electronic configuration will be:
σ1s2 σ∗1s2 σ2s2 σ∗2s2, &
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