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The Born-Haber cycle for KCl is evaluated with the following data:

Δ f H Θ     f o r     K C = − 4 3 6 . 7 k J m o l − 1 ; Δ s u b H Θ     f o r     K = 8 9 . 2 k J m o l − 1 ;

Δ i o n i z a t i o n H Θ     f o r     K = 4 1 9 . 0 k J m o l − 1 ;     Δ e l e c t r o n g a i n H Θ     f o r     C l ( g ) = − 3 4 8 . 6 k J m o l − 1 ;

Δ b o n d H Θ     f o r     C l 2 = 2 4 3 . 0 k J m o l − 1  

The magnitude of lattice enthalpy of KCl in kJ mol-1 is_________ (Nearest integer)

0 2 Views | Posted 3 months ago
Asked by Shiksha User

  • 1 Answer

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    Answered by

    Vishal Baghel | Contributor-Level 10

    3 months ago

    Δ H f 0 = ( + Δ H s u b 0 ) + ( + Δ H I E 0 ) + ( + 1 2 Δ H B D E 0 ) + ( Δ H E A 0 ) + ( − Δ H L E 0 )

    Δ H L E 0 = 8 9 . 2 + 4 1 9 + 1 2 1 . 5 − 3 4 8 . 6 + 4 3 6 . 7 k J m o l − 1

    ∴ Lattice energy = 717.8

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