The compound Na2IrCl6 reacts with triphenylphosphine in diethyleneglycol in an atmosphere of CO to give [IrCl(CO)(PPh3)2)], known as 'Vaska's compound'. (Atomic number of Ir = 77) Which of the following statements is correct?

(a) [1rCl (CO) (PPh3)2] carbonylchloridobis (triphenylphosphine) iridium (I). (b) Coordination number of Ir is four. Ir is in (+1) oxidation state with 4d8 configuration. It is trans isomer, so its geometry should be square planar. (c) All electrons are paired, hence diamagnetic (d) Can exhibit GI only.

The compound Na₂IrCl₆ reacts with triphenylphosphine in diethyleneglycol in an atmosphere of CO to give [IrCl(CO)(PPh₃)₂)], known as 'Vaska's compound'. (Atomic number of Ir = 77)

Which of the following statements is correct?

Option 1 - The IUPAC name of the complex is carbonylchlorideobis (triphenylphosphine) iridium(III)

Option 2 - The hybridization of the metal ion is sp3

Option 3 - The magnetic moment (spin only) of the complex is zero

Option 4 - The complex shows geometrical as well as ionization isomerism

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Answered by

Alok Kumar Singh | Contributor-Level 10

5 months ago

Correct Option - 3

Detailed Solution:

(a) [1rCl (CO) (PPh₃)₂] carbonylchloridobis (triphenylphosphine) iridium (I).

(b) Coordination number of Ir is four. Ir is in (+1) oxidation state with 4d⁸ configuration. It is trans isomer, so its geometry should be square planar.