The compound Na2IrCl6 reacts with triphenylphosphine in diethyleneglycol in an atmosphere of CO to give [IrCl(CO)(PPh3)2)], known as ‘Vaska’s compound’. (Atomic number of Ir = 77)
Which of the following statements is correct?
The compound Na2IrCl6 reacts with triphenylphosphine in diethyleneglycol in an atmosphere of CO to give [IrCl(CO)(PPh3)2)], known as ‘Vaska’s compound’. (Atomic number of Ir = 77)
Which of the following statements is correct?
Option 1 -
The IUPAC name of the complex is carbonylchlorideobis (triphenylphosphine) iridium(III)
Option 2 -
The hybridization of the metal ion is sp3
Option 3 -
The magnetic moment (spin only) of the complex is zero
Option 4 -
The complex shows geometrical as well as ionization isomerism
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1 Answer
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Correct Option - 3
Detailed Solution:(a) [1rCl (CO) (PPh3)2] carbonylchloridobis (triphenylphosphine) iridium (I).
(b) Coordination number of Ir is four. Ir is in (+1) oxidation state with 4d8 configuration. It is trans isomer, so its geometry should be square planar.
(c) All electrons are paired, hence diamagnetic
(d) Can exhibit GI only.
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