The conductivity of centimolar solution of KCl at 25°C is 0.0210 ohm-1 cm-1 and the resistance of the cell containing the solution at 25°C is 60 ohm. The value of cell constant is:

Option 1 - <p>3.34 cm⁻¹<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 2 - <p>1.34 cm⁻¹<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 3 - <p>3.28 cm⁻¹<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 4 - <p>1.26 cm⁻¹</p>
3 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
V
5 months ago
Correct Option - 4
Detailed Solution:

Conductivity = Conductance * Cell constant

Conductivity = (1/ resistance )

Cell constant = Conductivity * Resistance

Cell constant = 0.0210 * 60 = 1.26Cm? ¹

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